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CBSE Class 12-science Answered

find the molarity of 20% w/w NaOH
Asked by shipra015 | 08 May, 2020, 12:48: AM
answered-by-expert Expert Answer
consider space straight x space be space the space mass space of space solution

Mass space of space NaOH space equals space fraction numerator straight x space cross times 20 over denominator 100 end fraction

Molar space mass space of space NaOH space equals space 40 space straight g

therefore Number space of space moles space equals bevelled fraction numerator open parentheses fraction numerator 20 straight x over denominator 100 end fraction close parentheses over denominator 40 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals straight x over 200

Mass space of space the space solvent equals space straight x minus fraction numerator 20 straight x over denominator 100 end fraction equals fraction numerator 80 straight x over denominator 100 end fraction

therefore Molality space equals space fraction numerator left parenthesis straight x divided by 200 right parenthesis over denominator left parenthesis 80 straight x divided by 100 right parenthesis end fraction space cross times space 1000 space equals space 6.25 space straight M
Answered by Ramandeep | 08 May, 2020, 12:40: PM
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