Find the molality of solution formed by dissolving 2g of NaOH in 100g of water.

Asked by Bhanupriya Khurana | 7th Jul, 2013, 07:59: PM

Expert Answer:

Molecular weight of NaOH=23+1+16=40
number of moles=2g/40gmol-1
Molality=number of moles of solute/mass of solvent in (kg)
=2X 1000/100X40
=0.5molkg-1

Answered by  | 7th Jul, 2013, 09:34: PM

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