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CBSE Class 11-science Answered

find the minimum velocity for which the range is 39.2m
Asked by shivam upadhyaya | 10 Jun, 2013, 03:55: PM
answered-by-expert Expert Answer
range = v^2 sin2A/g where A is the angle at which projectile is launched and v is the velocity. 
 
v = sqrt(range*g/sin2A)
 
To find the minimum velocity, sin2A = 1
 
v = sqrt(39.2*9.8) = 19.6 m/s
Answered by | 11 Jun, 2013, 04:20: AM
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