find the maximum possible error in the measurement of the centripetal force on an object of mass m travelling at velocity v in a circle of radius r if m=3.5 +or- 0.1 kg,v=20 +or- 1 m/s and r =12.5 +or - o.5 m

Asked by fathimaansari | 15th Jan, 2012, 05:04: PM

Expert Answer:

        Centripetal force,  F = mv2/r

        ?F/F = (?m/m) + (2 ?v/v) + (?r/r)

               M= 3.5 +_0.1 kg

V= 20  +_1 m/s

R = 12.5+_ 0.5 m

 

?F/F = ( 0.1/3.5) +(2 x1/20) + (0.5/12.5)

       = 0.028571 +0.1 + 0.04

      =0.1685

maximum possible percentage error is:

(?F/F)x 100% =0.1685 x 100=16.8%

Answered by  | 15th Jan, 2012, 06:17: PM

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