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CBSE Class 9 Answered

<div>find the magnitude of gravitational force between earth and a satellite if the distance of satellite from the surface of earth is 700 km . mass of satellite is 1000kg .</div>
Asked by tinu1972 | 28 Jul, 2016, 07:27: PM
Expert Answer
begin mathsize 14px style straight F equals fraction numerator GM subscript straight E straight m over denominator open parentheses straight R plus straight h close parentheses squared end fraction
straight G equals 6.67 cross times 10 to the power of negative 11 end exponent space Nm squared divided by kg squared
straight M subscript straight E equals 6 cross times 10 to the power of 24 space kg
straight m equals 1000 space kg
straight R equals 6.4 cross times 10 to the power of 6 space straight m
straight h equals 700 space km equals 700 cross times 10 cubed space straight m
therefore straight F equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 6 cross times 10 to the power of 24 cross times 1000 over denominator open parentheses 6.4 cross times 10 to the power of 6 plus 700 cross times 10 cubed close parentheses squared end fraction
therefore straight F equals fraction numerator 4.002 cross times 10 to the power of 17 over denominator 5.041 cross times 10 to the power of 13 end fraction
therefore straight F equals 7.9 cross times 10 cubed space straight N end style
Answered by Romal Bhansali | 29 Jul, 2016, 11:58: AM

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