find the length of side of a square whose area is given (4xsquare+20x+25)cm
Asked by tanwardevdutt122
| 28th May, 2020,
10:30: AM
Expert Answer:
Area of the square = 4x2+20x+25 = (2x)2+2(2x)(5)+52
This is in the form a2+2ab+b2 and we know that a2+2ab+b2 = (a+b)2
Therefore, (2x)2+2(2x)(5)+52 = (2x+5)2
We know that, area of a square = side2
Here, area of square = (2x+5)2
side2 = (2x+5)2
Therefore, Length of side = (2x+5) cm.
Answered by Renu Varma
| 28th May, 2020,
11:10: AM
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