find the length of side of  a square whose area is given (4xsquare+20x+25)cm

Asked by tanwardevdutt122 | 28th May, 2020, 10:30: AM

Expert Answer:

Area of the square = 4x2+20x+25 = (2x)2+2(2x)(5)+52
This is in the form a2+2ab+b2 and we know that a2+2ab+b2 = (a+b)2
Therefore, (2x)2+2(2x)(5)+52 = (2x+5)2
We know that, area of a square = side2
Here, area of square = (2x+5)2
side2 = (2x+5)2
Therefore, Length of side = (2x+5) cm.

Answered by Renu Varma | 28th May, 2020, 11:10: AM