Find the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively.

Asked by Amyra B | 17th Apr, 2013, 06:46: PM

Expert Answer:

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively. Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).
 
Hence, 
398 - 7 = 391
436 - 11 = 425
542 - 15 = 527

Now, you can find the hcf(391, 425, 527) = 17
 
Hence, the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is 17.

Answered by  | 17th Apr, 2013, 08:56: PM

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