Find the first term&common diff. of A.P.
Asked by sunil_0010
| 1st Jul, 2009,
10:16: PM
Expert Answer:
let a and d be the first term and the common diff of the A.P.
sum of first 16 terms=16/2[2a+15d]=
16a+120d=528..(i)
sum of next 16 terms
=sum of first 32 terms - sum of first 16 terms
={32/2[2a+31d]}-{16/2[2a+15d]}
=16a+376d=1552..(ii)
solving,we get,
d=4
a=3
Answered by
| 2nd Jul, 2009,
10:38: AM
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