Find the first term&common diff. of A.P.

Asked by sunil_0010 | 1st Jul, 2009, 10:16: PM

Expert Answer:

let a and d be the first term and the common diff of the A.P.

sum of first 16 terms=16/2[2a+15d]=

16a+120d=528..(i)

sum of next 16 terms

=sum of first 32 terms - sum of first 16 terms

={32/2[2a+31d]}-{16/2[2a+15d]}

=16a+376d=1552..(ii)

solving,we get,

d=4

a=3

 

Answered by  | 2nd Jul, 2009, 10:38: AM

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