find the expansion of(x^2-2x+3)^3 using binomial theorem

Asked by  | 15th Nov, 2012, 11:02: AM

Expert Answer:

(x2-2x+3)3
= [x2-(2x-3)]3
= 3C0(x2)3 - 3C1(x2)2 (2x-3) + 3C2(x2) (2x-3)2 - 3C3 (2x-3)3
Simplify to get the desired result.

Answered by  | 15th Nov, 2012, 09:55: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.