Find the equations of the line passing through the point(1,-2,3) and parallel to the line (x-6)/3=(y-2)/(-4)=(z+7)/5

Asked by Manoj | 11th May, 2013, 06:35: AM

Expert Answer:

(x-6)/3=(y-2)/(-4)=(z+7)/5     
hence, the direction ratios of the line are (3,-4,5)
Since for a parallel line, the direction ratios remain the same, hence equation of line parallel to the given line and passing through (1,-2,3) is given by 
 
(x-1)/3 = (y+2)/(-4) = (z-3)/5

Answered by  | 11th May, 2013, 10:32: AM

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