Find the equations of the line passing through the point(1,-2,3) and parallel to the line (x-6)/3=(y-2)/(-4)=(z+7)/5
Asked by Manoj | 11th May, 2013, 06:35: AM
Expert Answer:
(x-6)/3=(y-2)/(-4)=(z+7)/5
hence, the direction ratios of the line are (3,-4,5)
Since for a parallel line, the direction ratios remain the same, hence equation of line parallel to the given line and passing through (1,-2,3) is given by
(x-1)/3 = (y+2)/(-4) = (z-3)/5
Answered by | 11th May, 2013, 10:32: AM
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