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CBSE Class 12-science Answered

Find the equation of the plane is . Find the perpendicular distance of the plane from the origin.
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
answered-by-expert Expert Answer

The given equation of the plane is .

Here,
Perpendicular distance of the plane from the origin is
units.
 
 
Answered by | 04 Jun, 2014, 15:23: PM

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CBSE 12-science - Maths
Q 48
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CBSE 12-science - Maths
If  is the normal from the origin to the plane, and  is the unit vector along . P(x, y, z) be any point on the plane and  is perpendicular to . Find the equation of plane in the normal form.
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Let  be the vector normal to the plane and  be the position vector of the point through which the plane passes. Then find the equation of plane.
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Find the equation of the plane whose distance from the origin is 8 units and the direction ratios of the normal are 6, – 3, – 2.
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CBSE 12-science - Maths
Find the equation of the plane is . Find the perpendicular distance of the plane from the origin.
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Find the co-ordinates of the foot of the perpendicular drawn from the origin to the plane 2x – 3y + 6z + 7 = 0.
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
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