Find the equation of the plane passing through the line of intersection of the planes x + y + z = 6, 3x + 2y + 6z + 15 = 0 and perpendicular to the plane 4x + 5y – 3z = 8.

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

The equation of the plane passing through the line of intersection of the planes x + y + z = 6, 3x + 2y + 6z + 15 = 0 is:

Since, the plane (1) is perpendicular to the plane 4x + 5y – 3z = 8,
Now, the required equation of the plane is:

Answered by  | 4th Jun, 2014, 03:23: PM