Find the equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 and the point (– 2, 1, 3).

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

The equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 is:

.
Also, the plane passing through the point (– 2, 1, 3),
Now, the required equation of the plane is:

Answered by  | 4th Jun, 2014, 03:23: PM