Find the equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 and the point (– 2, 1, 3).
Asked by Topperlearning User
| 4th Jun, 2014,
01:23: PM
Expert Answer:
The equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 is:
.Also, the plane passing through the point (– 2, 1, 3),
Now, the required equation of the plane is:
Answered by
| 4th Jun, 2014,
03:23: PM
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