Find the equation of a circle whose coordinates of the end points of the diameter are (-3,2) and (2,-4).

### Asked by Topperlearning User | 25th Apr, 2014, 09:11: AM

The equation of the circle when the end points of the diameter are given is (x - ) (x - ) + (y - ) (y - ) = 0.

Hence the equation is (x + 3) (x - 2) + (y - 2) (y + 4) = 0

or x^{2} + x - 6 + y^{2} + 2y - 8 = 0

or x^{2} + y^{2} - x + 2y - 14 = 0

### Answered by | 25th Apr, 2014, 11:11: AM

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