Find the equation of a circle whose coordinates of the end points of the diameter are (-3,2) and (2,-4).
Asked by Topperlearning User | 25th Apr, 2014, 09:11: AM
The equation of the circle when the end points of the diameter are given is (x - ) (x - ) + (y - ) (y - ) = 0.
Hence the equation is (x + 3) (x - 2) + (y - 2) (y + 4) = 0
or x2 + x - 6 + y2 + 2y - 8 = 0
or x2 + y2 - x + 2y - 14 = 0
Answered by | 25th Apr, 2014, 11:11: AM
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