find the domain and range of function

Asked by  | 2nd Oct, 2008, 09:21: AM

Expert Answer:

f(x) = 3 / 2 - x 2

For domain: 2 - x2  should not equal zero, i.e 2 shold not equal x 2

Domain { x : x R< x sq root 2}

For range

2y - x2y=3

x2= (2y-3)/y

x = Sq root  (2y-3)/y

For (2y-3)/y to be positive either both Nr and Dr should be positive , in which case y>3/2 . Or else both should be negative , in which case y <0.

Range  is therefore all  real numbers except between 0 and 3/2 , both included

Answered by  | 2nd Oct, 2008, 10:29: AM

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