CBSE Class 12-science Answered
Find the distance between the planes 2x – 2y + z + 3 = 0 and 6x – 6y + 3z + 5 = 0.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
The equations of the planes are:
2x – 2y + z + 3 = 0 …(1) and
6x – 6y + 3z + 5 = 0 …(2).
Perpendicular distance of the plane 2x – 2y + z + 3 = 0 from the origin is:
andPerpendicular distance of the plane 6x – 6y + 3z + 5 = 0 from the origin is:
.So, distance between the planes = 
Answered by | 04 Jun, 2014, 03:23: PM
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