Find the current in each resistor

Asked by najeeb.razvi
| 9th Aug, 2021,
06:45: PM
Expert Answer:
In the given circuit R1 and R4 are in series .
Hence Equivalent resistance R7 = 4Ω replaces resistors R1 and R4 in the circuit shown above.
Similarly , in the given circuit, R3 and R5 are in parallel.
Hence Equivalent resistance R6 = 4Ω replaces resistors R3 and R5 in the circuit shown above.
Let us assume the current distribution as shown in figure.
If we apply Kirchoff's voltage law to the loop ABEFA , we get
4
1 + 4
3 + 2 = 2 or
1 = -
3 ............................ (1)
If we apply Kirchoff's voltage law to the loop BCDEB , we get
4
1 + 4
2 + 2 = 2 or
1 = -
2 ...........................(2)
At node B , if we apply Kirchoff's current law , we get
1 =
2 +
3 ...............................(3)
From equations (1), (2) and (3) , we get ,
1 =
2 =
3 = 0
Hence current through all resistors is zero















Answered by Thiyagarajan K
| 9th Aug, 2021,
08:33: PM
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