CBSE Class 12-science Answered
Find the current in each resistor
Asked by najeeb.razvi | 09 Aug, 2021, 06:45: PM
Expert Answer
In the given circuit R1 and R4 are in series .
Hence Equivalent resistance R7 = 4Ω replaces resistors R1 and R4 in the circuit shown above.
Similarly , in the given circuit, R3 and R5 are in parallel.
Hence Equivalent resistance R6 = 4Ω replaces resistors R3 and R5 in the circuit shown above.
Let us assume the current distribution as shown in figure.
If we apply Kirchoff's voltage law to the loop ABEFA , we get
4 
1 + 4 3 + 2 = 2 or 1 = - 3 ............................ (1)
1 + 4 3 + 2 = 2 or 1 = - 3 ............................ (1)If we apply Kirchoff's voltage law to the loop BCDEB , we get
4 1 + 4 2 + 2 = 2 or 1 = - 2 ...........................(2)
1 + 4 2 + 2 = 2 or 1 = - 2 ...........................(2) At node B , if we apply Kirchoff's current law , we get 1 = 2 + 3 ...............................(3)
1 = 2 + 3 ...............................(3)From equations (1), (2) and (3) , we get , 1 = 2 = 3 = 0
1 = 2 = 3 = 0Hence current through all resistors is zero
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