FIND THE CENTRE,THE LENGHT of axes , eccentricity and the foci of the ellipse 12x^2+4y^2+24x-16y+25=0

Asked by  | 13th Mar, 2012, 10:23: PM

Expert Answer:

The given equation can be solved as follows
(x+1)2/4 + (y-2)2/(3/4) = 1
so , a = 2 , b = root(3) / 2
center is (-1,2)
eccentricity = root(1 - b2/a2) = root(13) / 4
focii is (+- root(13)/2 - 1 , 2)
Length of axes = 2a = 4

Answered by  | 14th Mar, 2012, 09:37: AM

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