find the center and the point from x2+y2+8x+10y-12=0.

Asked by  | 27th Dec, 2011, 11:39: AM

Expert Answer:

x2+8x+y2+10y-12=0
x2+8x+16+y2+10y+25-12-25-16=0
(x+4)2+(y+5)2 = 53
This eqn is of the form X2+Y2=R2
hence radius is x=-4 , y=-5

Answered by  | 27th Dec, 2011, 01:34: PM

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