CBSE Class 12-science Answered
Find the Cartesian equations of a line which passes through the point(1,2,3) and is parallel to the line
(-x-2)/1=(y+3)/7=(2z-6)/3
Asked by Manoj | 11 May, 2013, 06:30: AM
Expert Answer
(-x-2)/1=(y+3)/7=(2z-6)/3
(x+2)/(-1) = (y+3)/7 = (z-3)/(3/2)
Hence, the direction ratios of the line are (-1, 7, 3/2).
For parallel lines, the direction ratios remain the same, hence, the equation of line parallel to the given line but passing through (1,2,3) will be given by
(x-1)/(-1) = (y-2)/7 = (z-3)/3/2
(-x+1)/1 = (y-2)/7 = (2z-6)/3
Answered by | 11 May, 2013, 10:31: AM
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