Find the area of the polygon

Asked by sj596827 | 29th Jul, 2020, 05:58: PM

Expert Answer:

There are 4 triangles in the polygon and they are
ABF, BCF, CDF, DEF
straight A open parentheses increment ABF close parentheses equals 1 half cross times AG cross times BF equals 1 half cross times 2 cross times 6.5 equals 6.5 space cm squared
straight A open parentheses increment BCF close parentheses equals 1 half cross times BH cross times CF equals 1 half cross times 4 cross times 7 equals 14 space cm squared
straight A open parentheses increment CDF close parentheses equals 1 half cross times DI cross times CF equals 1 half cross times 4 cross times 7 equals 14 space cm squared
straight A open parentheses increment DEF close parentheses equals 1 half cross times EJ cross times DF equals 1 half cross times 2 cross times 5 equals 5 space cm squared
Area space of space polygon space ABCDEF equals Sum space of space areas space of space all space 4 space triangles space equals space 6.5 plus 14 plus 14 plus 5 equals 39.5 space cm squared

Answered by Renu Varma | 30th Jul, 2020, 11:14: AM