find the are of the region over lapped by the 2 semicircles

Asked by geethika | 11th Feb, 2010, 05:44: AM

Expert Answer:

Dear Student

Area of a segment is given by A=   

 

in the  given case     r=h= 4/2=2m

R=D/2= 4m

So the area of the region wich is overlapped by the 2 semicircles.

 2A=2[ 16 Xcos-1(1/2) - 2(16-4)   =32 pi/3 - 83 = 19.63 sq m

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Answered by  | 12th Feb, 2010, 12:45: PM

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