find the angle of projection at which the horizontal range and maximum height of a projectile are

Asked by  | 26th Jul, 2009, 01:05: AM

Expert Answer:

Let θ be the angle of projection for which horizontal range and maximum height of a projectile are equal.Now,

H= u2 sin2 θ / 2g

R = u2 sin2θ / g

So, if H=R

then , u2 sin2 θ / 2g = u2 sin2θ / g

or, sin2 θ / 2 = sin2θ

or, sin2 θ  =  2 (2 sinθ  cosθ )

or tan θ = 4

or, θ  = tan -1 ( 4)

Answered by  | 26th Jul, 2009, 12:45: PM

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