find the angle of projection at which the horizontal range and maximum height of a projectile are
Asked by | 26th Jul, 2009, 01:05: AM
Let θ be the angle of projection for which horizontal range and maximum height of a projectile are equal.Now,
H= u2 sin2 θ / 2g
R = u2 sin2θ / g
So, if H=R
then , u2 sin2 θ / 2g = u2 sin2θ / g
or, sin2 θ / 2 = sin2θ
or, sin2 θ = 2 (2 sinθ cosθ )
or tan θ = 4
or, θ = tan -1 ( 4)
Answered by | 26th Jul, 2009, 12:45: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change