CBSE Class 10 Answered

 Dear Student

a=AB=4CM, b=BC= 3CM, c=CD=3.5CM, d=DA= 3.5CM

Radius of the circumCircle R= (1/4A)(ab+cd)(ac+bd)(ad+bc)

s=(a+b+c+d)/2 =7

Where A= (s-a)(s-b)(s-c)(s-d)= 12.124

==> R=(1/48.5)24.25X24.5X24.5  =2.4876

θ_1, θ_2, θ_3, θ₄  are tne angles between radius and chord a,b,c,and d respectively.

θ₁= cos^-1( a/2R)= cos^-1(0.80)= 37

Similarly  θ₂=cos^-1( b/2R)=  53

θ₃=cos^-1( c/2R)=  45

θ₄  =45

A= θ₁+θ₄  =82

 B=θ₁+θ₂   =90

C= θ₂+θ₃  =98

D=θ₃ +θ₄  =90

Regards

Topperlearning team