Find number of atoms present in 11g of sodium
Asked by Bhanupriya Khurana | 7th Jul, 2013, 07:43: PM
Expert Answer:
Number of atoms present in 1mole of sodium=6.02X1023
1moleof sodium=23g
23g of sodium contains6.02X 1023 atoms
11g of soidum contains 6.02X 1023X11/23 atoms
=2.87X1023 atoms
Answered by | 8th Jul, 2013, 12:10: AM
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