Find integral zeros of 2xcube +3xsquare -8x-12

Asked by kinalsp | 20th Jun, 2018, 09:13: PM

Expert Answer:

2x+ 3x2 - 8x - 12
(x - 2)(2x2 + 7x + 6) = 0
(x - 2)(2x2 + 4x + 3x + 6) = 0
(x - 2)[2x(x + 2) + 3(x + 2)] = 0
(x - 2)(x + 2)(2x + 3) = 0
The zeroes of the polynomial are 2, -2, -3/2

Answered by Sneha shidid | 21st Jun, 2018, 09:56: AM

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