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find four numbers in AP, whose sum is 50 and in which the greatest number is 4 times the least
Asked by sonaisha | 09 Mar, 2009, 08:36: PM

Let the  four  numbers be

a-3d,a-d,a+d,a+3d  (imp step)

acc to qn

a-3d+a-d+a+d+a+3d=50

4a=50

a=25/2

Let d be positive, then the greatest number is a+3d

and

least number is a-3d

acc to qn

a+3d=4(a-3d)

15d=3a

5d=a

d=a/5=1/5*(25/2)=5/2

so the numbers in A.P. are

5,10,15,20

we see that their sum is 50

and

the greatest number i.e. 20 is four times the smallest number i.e. 5

Answered by | 10 Mar, 2009, 03:40: PM

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