CBSE Class 10 Answered
find four numbers in AP, whose sum is 50 and in which the greatest number is 4 times the least
Asked by sonaisha | 09 Mar, 2009, 08:36: PM
Expert Answer
Let the four numbers be
a-3d,a-d,a+d,a+3d (imp step)
acc to qn
a-3d+a-d+a+d+a+3d=50
4a=50
a=25/2
Let d be positive, then the greatest number is a+3d
and
least number is a-3d
acc to qn
a+3d=4(a-3d)
15d=3a
5d=a
d=a/5=1/5*(25/2)=5/2
so the numbers in A.P. are
5,10,15,20
we see that their sum is 50
and
the greatest number i.e. 20 is four times the smallest number i.e. 5
Answered by | 10 Mar, 2009, 03:40: PM
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