find dy/dx 

mention each and every formula and minute steps and detail

Y = xx . e(2x + 5)

Asked by haroonrashidgkp | 2nd Jun, 2018, 08:28: PM

Expert Answer:

y= xx . e(2x + 5)
Taking log on both sides,
log y = log [ xx . e(2x + 5) ]
log y = log xx + log  e(2x + 5)
log y = xlogx + 2x + 5
begin mathsize 16px style 1 over straight y dy over dx equals straight x cross times 1 over straight x plus logx space plus space 2
fraction numerator begin display style dy end style over denominator begin display style dx end style end fraction equals straight x to the power of straight x straight e to the power of 2 straight x plus 5 end exponent open parentheses 1 plus logx plus 2 close parentheses
fraction numerator begin display style dy end style over denominator begin display style dx end style end fraction equals straight x to the power of straight x straight e to the power of 2 straight x plus 5 end exponent open parentheses 3 plus logx close parentheses end style

Answered by Sneha shidid | 4th Jun, 2018, 10:29: AM