Find Distance(Reflection)
Asked by baidshryans | 1st Oct, 2008, 10:01: PM
Expert Answer:
image of P(-3,4) in the line y=3 will be P1(-3,2). only y coordinate will change such that the length of perpendicular remains same for the point and its image.
image of P1 in y=x will be P2(2,-3)
now distance between P and P2 =
(-3-2)2+(4-(-3))2 = (25+49) = 74
Answered by | 30th Nov, 2008, 02:36: AM
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