find distance of the point(1,2) from the line 4x + 7y +18= 0 along the line x-y=8.

Asked by  | 5th Mar, 2013, 01:06: PM

Expert Answer:

equation of line pependicular to the 4x+7y+18=0
and passing through (1,2)
perpendicular distance of (1,2) from the line 4x+7Y=8
angle between x-y=8 and 7x-4y=-1
distance of (1,2) from the line 4x+7y+18=0 along x-y=8

Answered by  | 6th Mar, 2013, 02:02: PM

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