find acube-bcube
Asked by
| 30th Aug, 2012,
05:41: PM
Expert Answer:
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
= 6(a^2 + b^2 + 20)
(a-b)^2 = a^2 + b^2 - 2ab
36 = a^2 + b^2 - 40
a^2 + b^2 = 76
Therefore,
a^3 - b^3 = 6(76 + 20) = 6 x 96 = 576
a^3 - b^3 = 6(76 + 20) = 6 x 96 = 576
Answered by
| 30th Aug, 2012,
05:53: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change