fast

Asked by  | 5th Aug, 2009, 02:47: PM

Expert Answer:

a – acceleration, u – initial velocity, v – final velocity, s – net displacement, t – time interval, Vavg – average velocity.

 

a = (v – u)/t

(v – u) = at

Multiply both sides by (v + u)

(v – u)(v + u) = at(v + u)

v2 – u2 = at(v + u),

For constant acceleration straight line motion,

Vavg = (u + v)/2 = s/t

(u + v) = 2Vavg = 2s/t

Using this result,

v2 – u2 = at(2s/t)

v2 – u2 = 2as

 

Regards,

Team,

TopperLearning.

 

 

 

 

Answered by  | 5th Aug, 2009, 07:07: PM

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