CBSE Class 9 Answered
Factorise : 64a^3 + 125y^3 - 64z^3 +240xyz
Asked by | 18 Sep, 2012, 12:11: PM
Expert Answer
64x3 + 125y3 - 64z3 + 240xyz
= (4x)3 + (5y)3 + (-4z)3 - 3(4x)(5y)(-4z)
= [(4x) + (5y) + (-4z)] [(4x)2 + (5y)2 + (-4z)2 - (4x)(5y) - (5y)(-4z) - (4x)(-4z)]
= (4x + 5y - 4z) (16x2 + 25y2 + 16z2 - 20xy + 20yz + 16zx)
Answered by | 18 Sep, 2012, 01:05: PM
Application Videos
Concept Videos
CBSE 9 - Maths
Asked by durgavenkatlakshmi1 | 20 Mar, 2024, 03:56: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by ammudeep0123 | 20 Mar, 2024, 07:13: AM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by jaswanthsompi12345 | 19 Dec, 2023, 06:54: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by rizwanmunna406 | 12 Dec, 2023, 10:09: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by sathishdoddamudigere2 | 01 Nov, 2023, 06:53: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by shambhushanker123 | 29 Oct, 2023, 08:36: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by artigupta0766 | 12 Oct, 2023, 11:47: PM
ANSWERED BY EXPERT
CBSE 9 - Maths
Asked by jhanvi3824 | 07 Oct, 2023, 09:35: PM
ANSWERED BY EXPERT