CBSE Class 10 Answered
expresss the HCF of 468 and 222 as 468x + 222y where x and y are integers in two different ways.
Asked by rajani.vinod | 02 Jun, 2019, 03:47: PM
Expert Answer
HCF of 468 and 222
468 = (222 x 2) + 24....(1)
222 = (24 x 9) + 6....(2)
24 = (6 x 4) + 0
Therefore, HCF = 6
6 = 222 - (24 x 9).....from(1)
= 222 - (468 – 222 x 2) x 9....from(2)
= 222 - (468 x 9 – 222 x 2 x 9)
= 222 - (468 x 9) + (222 x 18)
= 222 + (222 x 18) - (468 x 9)
= 222[1 + 18] – 468 x 9
= 222 x 19 – 468 x 9
= 468 x -9 + 222 x 19
Hence, HCF of 468 and 222 in the form of 468x + 222y is 468(-9)+ 222(19)
468 = (222 x 2) + 24....(1)
222 = (24 x 9) + 6....(2)
24 = (6 x 4) + 0
Therefore, HCF = 6
6 = 222 - (24 x 9).....from(1)
= 222 - (468 – 222 x 2) x 9....from(2)
= 222 - (468 x 9 – 222 x 2 x 9)
= 222 - (468 x 9) + (222 x 18)
= 222 + (222 x 18) - (468 x 9)
= 222[1 + 18] – 468 x 9
= 222 x 19 – 468 x 9
= 468 x -9 + 222 x 19
Hence, HCF of 468 and 222 in the form of 468x + 222y is 468(-9)+ 222(19)
Answered by Arun | 02 Jun, 2019, 08:48: PM
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