explain

Asked by  | 5th Jun, 2009, 11:10: PM

Expert Answer:

a2+b2+c2-ab-bc-ca=1/2(2a2+2b2+2c2-2ab-2bc-2ca)=1/2[(a-b)2 +(b-c)2 +(c-a)2 ]

Clearly the expression is always non negetive for real a,b & c

Answered by  | 7th Jun, 2009, 12:55: AM

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