Asked by spsberry8 | 25th Dec, 2009, 09:19: AM

Expert Answer:

For an adiabatic process,

P1V1γ = P2V2γ where γ = Cp/Cv which is always greater than 1 since Cp>Cv

V2/V1 = (P1/P2)1/γ

For an isothermal process,

P1V1 = P2V2


V2/V1 = P1/P2

Hence V2/V1 will always be greater in isothermal process than adiabatic process with same initial state.

Hence the expansion as well.







Answered by  | 25th Dec, 2009, 12:15: PM

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