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CBSE Class 11-science Answered

Explain with example Enthalpy of Solution.
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
answered-by-expert Expert Answer

Answered by | 04 Jun, 2014, 15:23: PM

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CBSE 11-science - Chemistry
state hess's law. how does it follow the first law of thermodynamics.
Asked by paulnaveed202 | 17 Dec, 2020, 12:36: PM
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CBSE 11-science - Chemistry
Give an example of application of Hess' Law.
Asked by Topperlearning User | 13 Aug, 2014, 16:24: PM
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CBSE 11-science - Chemistry
Explain with example Enthalpy of Solution.
Asked by Topperlearning User | 04 Jun, 2014, 13:23: PM
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CBSE 11-science - Chemistry
Compare lattice Enthalpy and Ionization Enthalpy.
Asked by Topperlearning User | 14 Aug, 2014, 09:38: AM
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CBSE 11-science - Chemistry
The enthalpy of combustion for H2, C (graphite) and CH4 are -285.8, -393.5, and -890.4 kJ/mol respectively. Calculate the standard enthalpy of formation ?Hf for CH4.
Asked by Topperlearning User | 15 Jun, 2016, 17:36: PM
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CBSE 11-science - Chemistry
Enthalpy of combustion of carbon graphite and carbon diamond is -293.5(kJ/mol) and - 670(kJ/mol) respectively. Calculate conversion of graphite into diamond.
Asked by Topperlearning User | 14 Aug, 2014, 09:58: AM
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CBSE 11-science - Chemistry
Define bond dissociation energy and mean bond dissociation energy.
Asked by Topperlearning User | 15 Jun, 2016, 17:35: PM
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CBSE 11-science - Chemistry
State "The Hess's law of constant summation".
Asked by Topperlearning User | 14 Aug, 2014, 10:15: AM
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CBSE 11-science - Chemistry
Show calculation of Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. from: Enthalpy changes of formation and bond enthalpies.
Asked by Topperlearning User | 14 Aug, 2014, 10:41: AM
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CBSE 11-science - Chemistry
Calculate the H of the following reaction, which describes the production of coal gas from carbon, given the steps below. H2O (g) + C (s) CO (g) + H2 (g) Given Steps H2 (g) + 1/2 O2 (g) H2O (g) H = - 242.0 kJ 2CO (g) 2 C (s) + O2 (g) H = + 221.0 kJ  
Asked by Topperlearning User | 15 Jun, 2016, 17:35: PM
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