Explain why a mixture of methanol and chloroform shows a positive deviation from Raoult's law?
Asked by valarmadhi_star | 28th Jun, 2010, 12:00: AM
Expert Answer:
In mixtures such as of methanol and chloroform shows a positive deviation from Raoult's Law, as the vapour pressure of the mixture is always higher than an ideal mixture. This is due to the fact that molecules are breaking away more easily than they do in the pure liquids. That is because the intermolecular forces between molecules of methanol and chloroform are less in a solution than they are in the pure liquids.
In mixtures such as of methanol and chloroform shows a positive deviation from Raoult's Law, as the vapour pressure of the mixture is always higher than an ideal mixture. This is due to the fact that molecules are breaking away more easily than they do in the pure liquids. That is because the intermolecular forces between molecules of methanol and chloroform are less in a solution than they are in the pure liquids.
Answered by | 17th Jul, 2010, 10:55: AM
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