explain impulse conduction through the axon?its generation and conduction?

Asked by Aksa Merin Saji | 28th Jan, 2014, 04:40: PM

Expert Answer:

In resting condition, the outer side of the nerve fibre carries positive charge i.e. more Na+ ions outside the axon membrane. This is called the polarised stated or polarisation of the nerve fibre. On stimulation, the axon membrane at the site of stimulation becomes more permeable to Na+ ions. Thus, Na+ ions move inwards and results is loss of polarisation which is known as depolarised state or depolarisation of the nerve fibre. Such region of the nerve fibre is known as the 'excited region'. The point of depolarisation becomes the stimulus for the next region of the axon membrane which in turn becomes depolarised. The previous region on the membrane becomes repolarised due to the active transport of Na+ ions to the outside of the membrane. Polarisation and depolarization of alternate region on the axon conducts the nerve impulse forward.

Answered by  | 28th Jan, 2014, 04:45: PM

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