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CBSE Class 12-science Answered

Explain: (i)The treatment of alkyl chlorides with aqKOH leads to the formation of alcohols,but in the presence of alcoholic KOH,alkenes are formed. (ii)Out of C6H5CH2Cl and C6H5ClC6H5 which is more easily hydrolysed by aqKOH and why?
Asked by banga71 | 13 Jan, 2018, 11:32: AM
answered-by-expert Expert Answer

(1) Alkyl chloride in presence of aqueous KOH gives the substituted product. In an aqueous solution, KOH completely ionizes to give hydroxide ions. OH- ion is a strong nucleophile, which can easily substitute the strong leaving chloride ion and leads to the formation of alcohol.

 R minus C l space space plus space a q. space K O H space rightwards arrow with blank on top space space R minus O H space space plus space space K C l
On other hand alkyl chloride containing β-hydrogen atom with alcoholic KOH solution undergo elimination reaction to give alkene as a major products. An alcoholic solution of KOH produce alkoxide (RO- ) ion, which is a strong base. It can easily abstract a β-carbon of alkyl chloride and form an alkene as a major product.
 R minus C H subscript 2 minus C H subscript 2 minus C l space space plus space space a l c o. K O H space rightwards arrow with blank on top space space R minus C H equals C H subscript 2 space space plus space space K C l space space plus space H subscript 2 O
space space space space space space space space beta space space space space space space space space space space alpha
 
(2) 
Answered by Ramandeep | 15 Jan, 2018, 09:42: AM

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