exercise 12 b numerical 2

Asked by nilesh.dhote74 | 31st May, 2020, 11:28: AM

Expert Answer:

Question - When four hydrogen nuclei combine to form a helium nucleus in the interior of sun, the loss in mass is 0.0265 a.m.u. How much energy is released ?

Solution- 

Given that Δm = 0.0265 a.m.u.

1 a.m.u. liberates 931.5 MeV of energy. Thus, energy liberated equivalent to 0.0265 a.m.u. is

 = 0.0265 a.m.u. × 931.5 MeV

 = 24.7 meV

Answered by Shiwani Sawant | 31st May, 2020, 12:58: PM