ICSE Class 10 Answered
exercise 12 b numerical 2
Asked by nilesh.dhote74 | 31 May, 2020, 11:28: AM
Expert Answer
Question - When four hydrogen nuclei combine to form a helium nucleus in the interior of sun, the loss in mass is 0.0265 a.m.u. How much energy is released ?
Solution-
Given that Δm = 0.0265 a.m.u.
1 a.m.u. liberates 931.5 MeV of energy. Thus, energy liberated equivalent to 0.0265 a.m.u. is
= 0.0265 a.m.u. × 931.5 MeV
= 24.7 meV
Answered by Shiwani Sawant | 31 May, 2020, 12:58: PM
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Radioactivity
Radioactivity, Nuclear Fission and Fusion
ICSE 10 - Physics
Asked by nilesh.dhote74 | 31 May, 2020, 11:28: AM
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