CBSE Class 9 Answered
exam
Asked by | 25 Jul, 2009, 06:04: AM
Expert Answer
consider triangles ABD,ACD
AB=AC (given triangle is equilateral)
angle ABD=angle ACD....(Each equal to 60 degrees given)
BD=CD..(Snce AD is median)
so
triangle ABD congruent to triangle ACD(SAS rule)
so,
angleBAD =angle CAD (C.P.C.T.)
Also
angle ADB=angle ADC (C.P.C.T.)...(i)
But they form a linear pair
so
ADB+ADC=180
So
2ADB=180...(from i)
So
ADB=90 degrees
AD perpen. to BC.
Answered by | 01 Aug, 2009, 10:05: AM
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