CBSE Class 9 Answered
exam
Asked by | 25 Jul, 2009, 06:10: AM
Expert Answer
angle ABC= angleACB (Since AB=AC given)
let
ABC=ACB=x (say)
then
DAC=ABC+ACB=2x..(ext angle is equal to sum of int opp angles)
so
EAC=1/2[DAC]=x..(since AE bisects DAC given)
So for lines BC and AE, with AC as transversal,
EAC=ACB...(each equal to x)
so
BC parallel to AE..(alt int angles are equal)
Answered by | 01 Aug, 2009, 10:47: AM
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