Asked by | 25th Jul, 2009, 05:26: AM
consider the angle BAC and its internal bisector AD.
Take any point P on AD.
Drop perpendiculars PE and PF on BA and AC respectively.
in right triangles,
angle EAP=angle FAP...AD is bisector given
angle APE= angle APF...90 degrees each
so the triangles are congruent by RHS rule.
Answered by | 9th Aug, 2009, 12:17: AM
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