EXAM TOMORROW .ANSWER IMMEDIATELY!!!!!!!!!!!
Asked by vidyatmika | 9th Jan, 2010, 09:06: PM
Let x be the work done by a man in one day, and y be the same for a woman,
1 piece of work = 6(6x + 5y).............1/6 = 6x + 5y
1 piece of work = 10(3x + 4y)...........1/10 = 3x + 4y
Solving these simultaneously we find,
x = 1/54, y = 1/90
1 piece of work = D(9x + 15y)
where D is the number of days required as in the question.
D = 1/(9(1/54) + 15(1/90)) = 3 days.
Answered by | 10th Jan, 2010, 12:43: AM
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