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CBSE Class 12-science Answered

Evaluate sin to the power of negative 1 end exponent open parentheses sin fraction numerator 2 straight pi over denominator 3 end fraction close parentheses
Asked by Topperlearning User | 21 Apr, 2016, 10:42: AM
answered-by-expert Expert Answer

sin to the power of negative 1 end exponent open parentheses sin fraction numerator 2 straight pi over denominator 3 end fraction close parentheses not equal to fraction numerator 2 straight pi over denominator 3 end fraction
as space space fraction numerator 2 straight pi over denominator 3 end fraction space does space not space lie space between space minus straight pi over 2 space and space straight pi over 2
therefore sin to the power of negative 1 end exponent open parentheses sin fraction numerator 2 straight pi over denominator 3 end fraction close parentheses equals sin to the power of negative 1 end exponent open parentheses sin space open parentheses straight pi space minus straight pi over 3 close parentheses close parentheses equals Sin to the power of negative 1 end exponent open parentheses sin space straight pi over 3 close parentheses equals straight pi over 3
open square brackets because sin open parentheses straight pi minus straight theta close parentheses equals sinθ close square brackets

 

 

 

Answered by | 21 Apr, 2016, 12:42: PM

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