Evaluate the following:

Asked by Annette | 3rd Oct, 2009, 01:28: PM

Expert Answer:

x = acos3B; y = asin3B

x/a = cos3B; y/a = sin3B

(x/a)2/3 + (y/a)2/3 = (cos3B)2/3 + (sin3B)2/3................{ (xy)z = xyz }

= cos2B + sin2B = 1

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Answered by  | 3rd Oct, 2009, 08:23: PM

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