Evaluate please
Asked by vshrikanth | 6th Mar, 2010, 11:25: AM
Expert Answer:
x3 + y3 + z3 = 3xyz if x + y + z = 0
Here,
x- a + x - b + x-c = 3x - (a+ b+ c)
= 3x - 3x (Given)
= 0
(x-a)3+(x-b)3+(x-c)3 = 3 (x-a)(x-b)(x-c)
So, (x-a)3+(x-b)3+(x-c)3 - 3 (x-a)(x-b)(x-c) = 0
Answered by | 6th Mar, 2010, 12:36: PM
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