Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Evaluate cot 12 cot 38 cot 52 cot 60 cot 78
Asked by sadhanapatil494 | 13 Jan, 2020, 08:02: PM
answered-by-expert Expert Answer
cot12° cot38° cot52° cot60° cot78°
= (cot12°× cot78°)(cot38° cot52°) cot60° 
=[cot12°×cot(90° - 12º)][cot38°×cot(90° - 38º) cot60° 
cot12°× tan12°× cot38°× tan38°× cot60° 
= 1 × 1× cot60° 
= 1/2
Answered by Yasmeen Khan | 14 Jan, 2020, 10:34: AM

Application Videos

CBSE 10 - Maths
Asked by vk952384 | 09 Mar, 2024, 11:34: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ankitakulhar075 | 03 Apr, 2022, 08:43: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by arunpattu22 | 11 Jun, 2021, 11:21: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by debasreepartha | 23 Apr, 2021, 08:38: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by lavanyasureshkumar | 24 Aug, 2020, 04:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by meenakshisrinivas4 | 20 Apr, 2020, 12:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by Maharanam446 | 22 Jan, 2020, 01:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by sadhanapatil494 | 13 Jan, 2020, 08:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by preetisonips22 | 04 Jan, 2020, 05:44: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shethdhrumil0 | 20 Dec, 2019, 12:09: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×