Evaluate: ((1+sin2x)/(x+〖sin〗^2 x))dx

Asked by Manoj | 9th Mar, 2013, 07:08: AM

Expert Answer:

Let x+sin2x = t
Then, (1+2sinxcosx) dx = dt , i.e., (1+sin2x)dx = dt
 
Therefore, 
I = dt/t = logt + c = log(x+sin2x) + c
 

Answered by  | 10th Mar, 2013, 04:50: PM

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